Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (imstuck):

Trig problem! Help!

OpenStudy (imstuck):

2 sin(2x) - 1 = 0

OpenStudy (anonymous):

sin (2x)=

OpenStudy (imstuck):

The instructions are to solve for the principle values of x. Sorry I forgot to post that!

OpenStudy (imstuck):

sin(2x) = 2 sin(x)cos(x)

OpenStudy (anonymous):

No need to go so far yet. From the problem give, sin(2x)=1/2 OK?

OpenStudy (imstuck):

Got that. I even moved the -1 over and had this: 2(sin x)(cos x) = 1 (sin x)(cos x)= 1/2

OpenStudy (imstuck):

sin(2x) = 1/2, ok...

OpenStudy (anonymous):

No, no need to break down into sinx cosx if sin(2x)=1/2 then what is 2x=

OpenStudy (imstuck):

I don't understand what is 2x...

OpenStudy (anonymous):

\[2*sin(2x)-1=0\]\[2*sin(2x)=1\]\[sin(2x)=\frac{1}{2}\]\[2x=arcsin\left(\frac{1}{2}\right)\]\[x=15^o=\frac{\pi}{12}~rad~~or~~x=75^o=\frac{5\pi}{12}~rad\]

OpenStudy (anonymous):

OK @D3xt3R gave you the answer

OpenStudy (imstuck):

But I don't understand how 2x = arcsin. Please explain that part.

OpenStudy (imstuck):

I really appreciate the answer, but I don't get the mechanics of it so it doesn't help me.

OpenStudy (anonymous):

arcsin = inverse function of sin for exemple:\[sin(x)=1\]x could be 90º, if we got \[sin(2x)=1\]x could be 45º, because 2x45º = 90º, isn't it?! we just call arcsin the inverse funtion of sin, and we got and angle

OpenStudy (imstuck):

How do you identify the inverse functions? Are they always denoted with a (2x) or something? How do you know when you are dealing with one, @D3xt3R

OpenStudy (imstuck):

So sin(2x) will always mean arcsin? cos(2x) will always mean arccos? and tan(2x) will always mean arctan?

OpenStudy (anonymous):

exactly

OpenStudy (imstuck):

oh wow! So that's how you know you're dealing with the inverses? Very cool to know! Thank you so much!

OpenStudy (anonymous):

Be careful. the inverse function of sin(x) is arcsin the inverse function of cos(x) is arccos the inverse function of tan(x) is arctan

OpenStudy (anonymous):

the inverse function of sin(2x) is \[\frac{arcsin}{2}\]

OpenStudy (imstuck):

I see how I mistook what you said.

OpenStudy (imstuck):

This is all very confusing at first.

OpenStudy (anonymous):

If you have a problem like "What x give us sin(x)=1" Now you have to find the value of x using inverse function

OpenStudy (imstuck):

so if there's something other than an (x) inside the parenthesis, you're dealing with something other than just a plain old angle?

OpenStudy (imstuck):

I know half angles, I thought maybe this was a double angle. How come it's not? I just don't understand how I am supposed to just KNOW that this isn't a double angle thing but an inverse function thing.

OpenStudy (anonymous):

I prefere to use x inside the parenthesis, many people don't use this. they just write sinx

OpenStudy (imstuck):

Look to my question just above, if you would, and answer it for me?

OpenStudy (imstuck):

OH WAIT! I know it's an inverse because I have to divide by the sin function to get the 2x alone to solve for x, right?

OpenStudy (anonymous):

yes

OpenStudy (imstuck):

Thank you. I have another 2 trig problems that were kicking my butt...I'll post in a separate post so as to medal you for your help if you care to pop in and look at it.

OpenStudy (anonymous):

OK, thanks. Mark me there ;)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!