Trig problem! Help!
2 sin(2x) - 1 = 0
sin (2x)=
The instructions are to solve for the principle values of x. Sorry I forgot to post that!
sin(2x) = 2 sin(x)cos(x)
No need to go so far yet. From the problem give, sin(2x)=1/2 OK?
Got that. I even moved the -1 over and had this: 2(sin x)(cos x) = 1 (sin x)(cos x)= 1/2
sin(2x) = 1/2, ok...
No, no need to break down into sinx cosx if sin(2x)=1/2 then what is 2x=
I don't understand what is 2x...
\[2*sin(2x)-1=0\]\[2*sin(2x)=1\]\[sin(2x)=\frac{1}{2}\]\[2x=arcsin\left(\frac{1}{2}\right)\]\[x=15^o=\frac{\pi}{12}~rad~~or~~x=75^o=\frac{5\pi}{12}~rad\]
OK @D3xt3R gave you the answer
But I don't understand how 2x = arcsin. Please explain that part.
I really appreciate the answer, but I don't get the mechanics of it so it doesn't help me.
arcsin = inverse function of sin for exemple:\[sin(x)=1\]x could be 90º, if we got \[sin(2x)=1\]x could be 45º, because 2x45º = 90º, isn't it?! we just call arcsin the inverse funtion of sin, and we got and angle
How do you identify the inverse functions? Are they always denoted with a (2x) or something? How do you know when you are dealing with one, @D3xt3R
So sin(2x) will always mean arcsin? cos(2x) will always mean arccos? and tan(2x) will always mean arctan?
exactly
oh wow! So that's how you know you're dealing with the inverses? Very cool to know! Thank you so much!
Be careful. the inverse function of sin(x) is arcsin the inverse function of cos(x) is arccos the inverse function of tan(x) is arctan
the inverse function of sin(2x) is \[\frac{arcsin}{2}\]
I see how I mistook what you said.
This is all very confusing at first.
If you have a problem like "What x give us sin(x)=1" Now you have to find the value of x using inverse function
so if there's something other than an (x) inside the parenthesis, you're dealing with something other than just a plain old angle?
I know half angles, I thought maybe this was a double angle. How come it's not? I just don't understand how I am supposed to just KNOW that this isn't a double angle thing but an inverse function thing.
I prefere to use x inside the parenthesis, many people don't use this. they just write sinx
Look to my question just above, if you would, and answer it for me?
OH WAIT! I know it's an inverse because I have to divide by the sin function to get the 2x alone to solve for x, right?
yes
Thank you. I have another 2 trig problems that were kicking my butt...I'll post in a separate post so as to medal you for your help if you care to pop in and look at it.
OK, thanks. Mark me there ;)
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