According to the formula for stopping distance, how many feet will it take you to stop, from 60 mph?
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It depends upon ur deacceleration.
or coefficient of friction as v=\(\sqrt{2\mu gd}.\)
where, V = initial velocity, μ=coefficient of friction, d=breaking distance, g=accl due to gravity
http://wiki.answers.com/Q/How_long_does_it_take_to_stop_from_65_mph This man know how to make approximations :D
He assumed (the one who answered the question in the link given) the deaccelaration 1G himself.
Yea. I think this problem needs such a thing.Anyway it should be mention in the course which asked this.
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