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Physics 15 Online
OpenStudy (anonymous):

According to the formula for stopping distance, how many feet will it take you to stop, from 60 mph?

OpenStudy (abhisar):

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OpenStudy (abhisar):

It depends upon ur deacceleration.

OpenStudy (abhisar):

or coefficient of friction as v=\(\sqrt{2\mu gd}.\)

OpenStudy (abhisar):

where, V = initial velocity, μ=coefficient of friction, d=breaking distance, g=accl due to gravity

OpenStudy (anonymous):

http://wiki.answers.com/Q/How_long_does_it_take_to_stop_from_65_mph This man know how to make approximations :D

OpenStudy (abhisar):

He assumed (the one who answered the question in the link given) the deaccelaration 1G himself.

OpenStudy (anonymous):

Yea. I think this problem needs such a thing.Anyway it should be mention in the course which asked this.

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