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Mathematics 7 Online
OpenStudy (vishweshshrimali5):

Quotient Rule Derivation Using Product Rule

OpenStudy (vishweshshrimali5):

Quotient Rule basically says that: \[\large{\cfrac{d}{dx}(\cfrac{u(x)}{v(x)}) = \cfrac{u'(x)v(x) - v'(x)u(x)}{(v(x))^2}}\]

OpenStudy (vishweshshrimali5):

Now product rule states that: \[\large{(fg)' = f'g + gf'}\] Now let: f(x) = u(x) and \(\large{g(x) = \cfrac{1}{v(x)}}\) Then, using product rule we have: \[\large{(fg)' = f'g + fg'}\] Now, \[\large{f'(x) = u'(x)}\] and \[\large{g'(x) = -\cfrac{1}{(v(x))^2}\cdot v'(x)}\]

OpenStudy (vishweshshrimali5):

Thus we have: \[\large{(fg)' = f'g + fg'}\] \[\large{\implies (fg)' = -u(x)\cdot\cfrac{v'(x)}{(v(x))^2} + u'(x)\cdot \cfrac{1}{v(x)}}\] \[\large{\implies (u/v)' = \cfrac{vu' - uv'}{v^2}}\] Well pretty easy and basic. Similarly, we can find out the similarity between different formulae which are basically the same.

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