When solving x2 + 6x = 10 by the completing the square method, what value is added to both sides?
9
5
4
3
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OpenStudy (superhelp101):
@jim_thompson5910
OpenStudy (superhelp101):
@satellite73
OpenStudy (superhelp101):
@Hero @ganeshie8
OpenStudy (superhelp101):
@zzr0ck3r @SithsAndGiggles
OpenStudy (superhelp101):
@dumbcow
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OpenStudy (superhelp101):
@aum I need your help
OpenStudy (superhelp101):
@Luigi0210 @phi
OpenStudy (anonymous):
How would you get \((x+3)^2\) on the right side?
OpenStudy (superhelp101):
wait how did you get that. may i ask you to please explain?
OpenStudy (anonymous):
Expanding the binomial gives you
\[(x+3)^2=x^2+6x+9\]
The trick to completing the square is to find a number (in this case 9) such that when you take the square root and double it, you get the coefficient of the \(x\) term.
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OpenStudy (anonymous):
In reverse order, you're given the coefficient, so you would cut it in half and square it:
\[\left(\frac{6}{2}\right)^2=3^2=9\]