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Mathematics 13 Online
OpenStudy (anonymous):

please help me

OpenStudy (anonymous):

A rectangular plank sqrt(2) meter wide is placed symmetrically on the diagonal of a square of side 8 meters, as shown in the figure.

OpenStudy (anonymous):

OpenStudy (anonymous):

find the area of the plank

OpenStudy (anonymous):

area of a square=64

OpenStudy (anonymous):

length*sqrt(2)=area of rectangle

OpenStudy (anonymous):

help me @AriPotta

OpenStudy (driftracer305):

area of plank is 14 m^2

OpenStudy (anonymous):

how.@driftracer305

OpenStudy (driftracer305):

k if you have seen something like a ratio of a 45-45-90 triangle that is 1:1: sqrt2..... have you?

OpenStudy (driftracer305):

@svi ?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

@driftracer305

OpenStudy (driftracer305):

k so in the same sense.... like a small corner formed..... the hypotenuse is sqrt2.... so the remaining 2 sides are 1........... and now the length of square is 8 so if you subtract 1 u get 7.........

OpenStudy (dumbcow):

|dw:1405405372838:dw| \[(7\sqrt{2})*\sqrt{2} = 7*2 = 14\] that should help

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