jim_thompson5910 help me:(sin A-cos A+1)/(sin A+cos A-1)=1/(tan A+sec A)
@jim_thompson5910 .
1/(sina/cosa+1/cosa)
See what you get when you combine sina/cosa+1/cosa
I'm not sure how you'd turn it into the left side though
to get in terms of sin ,cos.if it is wrong?.explain
(sina-cosa+1)/(sina+cosa-1)*(sina-cosa+1)/sina-cosa+1)
hmm that might work, see what happens when you expand it out
2/sina cosa+
(sin^a+cosa sina -sina-cosa sina-cos^a+cosa +sina+cosa+1)/(sin^2a+sinacosa+sina+cosasina+cos^2a+cosa-sina-cosa-1)
definitely a mess, but maybe a few things cancel?
wait this is not an identity ... are we solving for "a" ?
please specify whether the problem is to verify an identity or solve for a variable you can waste a ton of time trying to match both sides when its actually impossible :)
i think it is proving
as u said it is correct .it is not showing the answer
k .i will close it
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