SOMEONE PLEASE HELP ME!! The picture shows a triangular island: A right triangle is shown with an acute angle equal to 55 degrees. The length of the side of the triangle opposite to the acute angle is r. The length of the side of the triangle adjacent to the acute angle is s. The length of the hypotenuse is q. Which expression shows the value of q? ANSWERS r cos 55° r sin 55° s over sin 55 degrees s over cos 55 degrees
\[\sin(55)=\frac{r}{q}\]
also \[\cos(55)=\frac{s}{q}\]
we can solve either one of those for \(q\)
i don't really know how to solve these though
ok lets do the first one
\[\sin(55)=\frac{s}{q}\\ q\sin(55)=s\\ q=\frac{s}{\sin(55)}\]
ok how do i solve that though
i am not sure what you are asking
you don't have numbers for \(r,s, q\) just letters your answer choices all have variables in them, you cannot get a number out of this
i don't know how to do these equations is what i'm trying to say
but you're saying the answer would be c?
oh i got \[\sin(55)=\frac{r}{q}\] using "sine is opposite over hypotenuse"
ohh okay! i understand this
but no, the answer is not C
\[\cos(55)=\frac{s}{q}\iff q=\frac{s}{\cos(55)}\]
so you flip the equation?
sort of depends on what you are solving for
\[3=\frac{12}{x}\iff x=\frac{12}{3}\]
i see
i would go with D in this case don't get confused by the sine and cosine you solve a proportion the way you always do
okay thank you!
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