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Mathematics 15 Online
OpenStudy (anonymous):

Two ropes, AD and BD, are tied to a peg on the ground at point D. The other ends of the ropes are tied to points A and B on a flagpole, as shown below: Two ropes, AD and BD, are tied to a peg on the ground at point D. The other ends of the ropes are tied to points A and B on a flagpole. Angle ADB measures 60 degrees and angle BDC measures 30 degrees. The length of DC is 10 multiplied by square root of 3. Angle ADC measures 60° and angle BDC measures 30°. What is the distance between the points A and B on the flagpole? 40 feet 20 feet 30 feet 10 feet

OpenStudy (anonymous):

OpenStudy (anonymous):

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OpenStudy (anonymous):

so it's tangent?

OpenStudy (anonymous):

the short side of that large triangle is \(10\sqrt3\) so the long side is \(10\sqrt3\times \sqrt3=30\)

OpenStudy (anonymous):

i'm so confused what

OpenStudy (anonymous):

in other words \(AC=30\)

OpenStudy (anonymous):

you have two triangles lets forget about trig, and concentrate on the large triangle the ratios of a 30 -60 - 90 triangle are \[1:\sqrt3:2\] for short side : long side : hypotenuse your short side is \(10\sqrt3\) so the long side is \(10\sqrt3\times \sqrt3=30\) i.e. \[AC=30\]

OpenStudy (anonymous):

this isn't making any sense to me

OpenStudy (anonymous):

sorry

OpenStudy (anonymous):

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OpenStudy (anonymous):

|dw:1405421729703:dw|

OpenStudy (anonymous):

so \(AC=30\) but that doesn't answer the question because you don't want \(AC\)

OpenStudy (anonymous):

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OpenStudy (anonymous):

you want \(AB=AC-BC=30-10=20\)

OpenStudy (anonymous):

ok but what would the answer be

OpenStudy (anonymous):

20

OpenStudy (anonymous):

thank you!

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