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OpenStudy (anonymous):
well first write everything you see in that phrase
OpenStudy (anonymous):
like 6 , x^4 , x^3 and etc.write all of them.
OpenStudy (anonymous):
extract 6 outside
OpenStudy (anonymous):
@Ankh , DON"T just give answers ! he/she wants to be assisted!
OpenStudy (anonymous):
@Twilliams250 , so we have 6, x^4 , x^3 , x^2 , 12
between 6 and 12, 12 is less than 12.so we write 6:
6 ....
and between x^4 , x^2 , x^3 which of them is the least?
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OpenStudy (anonymous):
x^2
OpenStudy (anonymous):
6x^4 + 6x^3 -12x^2 (get the biggest number you can think of out of all members)
You see the biggest one is 6x^2
if you remove 6x^2 from each member, you get:
x^2+x-2
Keep in mind you still have to put 6x^2 somewhere
But first let's deal with x^2+x-2
If you solve this using the quadratic formula you get the answers x=1, x=-2
what nullifies those numbers? their opposites, therefore (x+2)(x-1)
And remember that 6x^2? you just have to add it now:
6x^2(x+2)(x-1)
OpenStudy (anonymous):
so we write x^2 too:
6x^2 ...
and then find this:
\[\frac{ 6x ^{4} + 6x ^{3} - 12x ^{2} }{ 6x ^{2} }\]
OpenStudy (anonymous):
so you got your last question?
first let's factor 2x +8
between 2 and 8, 2 is the least number so we write 2 ...
and then 2 times x + 4 would be 2x + 8 so we write 2(x+4) ok then
OpenStudy (anonymous):
and for xy + 4 we can't factor anything!
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OpenStudy (anonymous):
so it would be :
2(x+4)(xy+4)
OpenStudy (anonymous):
got it?
OpenStudy (anonymous):
ok,ask
OpenStudy (anonymous):
let f(x)=1-x+x^2 and g(x)=1+x then f(x)g(x) equals
A.1-x+x^2=x^3
B.1-x+x^3
C.1-x^2+x^3
D.1+x^3
OpenStudy (anonymous):
you mean f(x) . g(x) or f(g(x)) ?
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OpenStudy (anonymous):
f(x)g(x)
OpenStudy (anonymous):
well, i think it's f(x) . g(x) .
f(x) = 1 - x + x^2
g(x) = 1 + x
so you only need to find (1 - x + x^2)(1-x)
;)
OpenStudy (anonymous):
and can you do the rest ?
OpenStudy (anonymous):
trying
OpenStudy (anonymous):
@Twilliams250 , found it?
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OpenStudy (anonymous):
noo can u help
OpenStudy (anonymous):
sry, i didn't see your comment .
yes.first find (1-x+x2)(1)
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
i think the answer would be A is that correct
OpenStudy (anonymous):
no,the thing is that none of them is the answer!
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OpenStudy (anonymous):
what should i do thats a queston on my quiz im taking
OpenStudy (anonymous):
oh sorry wait a moment! i made a mistake :D :P
OpenStudy (anonymous):
yes i found the answer,it isn't A.try it again.
OpenStudy (anonymous):
o k
OpenStudy (anonymous):
i got c this time
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OpenStudy (anonymous):
this is false again :D
OpenStudy (anonymous):
how do u get these answers?
OpenStudy (anonymous):
d?
OpenStudy (anonymous):
yes,this time it's correct :)
OpenStudy (anonymous):
so u got it?
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OpenStudy (anonymous):
yea i may have another ?
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
Let f(x)=x^1999 and g(x)=2x-x^5.Then f(x)G(x) equals
A. 2x^2000-x^2004
B.(2x-x^5)^1999
C. 2x1999-x9995
D.2x-x^5+x^1999
OpenStudy (anonymous):
again you should find:
(x^1999)(2x - x^5) = ?
OpenStudy (anonymous):
ok
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OpenStudy (anonymous):
well,what did you find?
OpenStudy (anonymous):
C
OpenStudy (anonymous):
let me check
OpenStudy (anonymous):
no no you're incorrect,check it again.
OpenStudy (anonymous):
D?
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OpenStudy (anonymous):
no :D
OpenStudy (anonymous):
ok let me try again
OpenStudy (anonymous):
B!
OpenStudy (anonymous):
\[a(c+b) = ac + ab\]
OpenStudy (anonymous):
NO! A :|
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Ok i got another ?
Which of the following polynomials in standard form is equivalent to the polynomial below
(x^2y+y^3)(x+xy^2)
A.x^3y+xy^3
B.x^3y+xy^3+x+xy^2
C.x^3y+xy^3+x^3y^3+xy^5
D.x^2y+y^3+x+xy^2
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OpenStudy (anonymous):
first do the multiplication...
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
i got D
OpenStudy (anonymous):
no D is incorrect :) solve these questions carefully!
OpenStudy (anonymous):
A
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OpenStudy (anonymous):
no!
OpenStudy (anonymous):
can u explain
OpenStudy (anonymous):
\[(x ^{1999} ) (2x - x ^{5}) = {(x ^{1999})(2x)} - {(x ^{1999})(x ^{5}) } \]
just like it!
OpenStudy (anonymous):
ok let me try
OpenStudy (anonymous):
B i think i got it
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OpenStudy (anonymous):
no C!
OpenStudy (anonymous):
ok got 5 more ? on the quiz
OpenStudy (anonymous):
ok,go on.
OpenStudy (anonymous):
@Twilliams250 , where are u ? :D
OpenStudy (anonymous):
give all the 5 questions together.
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OpenStudy (anonymous):
is it true that x^a x x^b=x^b x x^a. which property of the of polynomial multplication ensures the equality
A. Associative
B.commutative
C.Distributive
OpenStudy (anonymous):
it's B; we call this rule "commutative"
OpenStudy (anonymous):
let f(x)=11-25x-3x^2+4x^3 and g(x)=-3+11x-25x^2 Then F(x)+G(x) equals
A. 8+14x-28x^2
B.8-14x-28x^2+4x^3
C. 8+14X-28x^2+4x^3
D.8-14x-28x^2
OpenStudy (anonymous):
what's your idea?
OpenStudy (anonymous):
@Twilliams250
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OpenStudy (anonymous):
@Twilliams250 , WHERE ARE YOU?
OpenStudy (anonymous):
sry @Twilliams250 please hurry up.where have u gone? :D
OpenStudy (anonymous):
is the answer B
OpenStudy (anonymous):
yes ;)
OpenStudy (anonymous):
so you're becoming skillful to solving these sorts of questions ;)
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OpenStudy (anonymous):
let f(x) be a fifth degree polynomial and G(x) also be a fifth degree polynomial the degree of f(x)+G(x) must also equal 5
A True
B False
OpenStudy (anonymous):
what's your idea?
OpenStudy (anonymous):
what
OpenStudy (anonymous):
what's your idea/what's your answer to this question?
OpenStudy (anonymous):
what do u think?
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OpenStudy (anonymous):
i think true
OpenStudy (anonymous):
yes ;) true
OpenStudy (anonymous):
are u shore that the answer ?
OpenStudy (anonymous):
yes it's true
OpenStudy (anonymous):
(1+x)(1+y)
A. x+y
B.1+x+y+xy
C.1+x+y
D.1+xy
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OpenStudy (anonymous):
what's your idea?
OpenStudy (anonymous):
@Twilliams250 , why are you waiting so much?
OpenStudy (anonymous):
i think a
OpenStudy (anonymous):
how (1+x)(1+y) could be x+y?
(1+x)(1+y) = 1(1+y) + x(1+y) = ?
OpenStudy (anonymous):
oh is it B
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