Question

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Answer 1

A train starts from rest moves with a constant acceleration of 2m/s^2 for half a minute. The brakes are then applied and then train comes to rest in one minute after applying breaks.
Find (a)The total distance moved by the train,
(b)the maximum speed attained by the train and
(c) the position(s) of the train at half the maximum speed

Answer 2

@Miracrown

Answer 3

V^2 = Vo^2 + 2ad
a=(V^2-Vo^2)/2d=(900-0)/7400=0.122 m/s^2

d2 = 30m/s * 410s = 12300 m.

d3 = (V^2-Vo^2)/2a
d3 = (0-900)/-0.130

Answer 4

And that equals?????

Answer 5

it's incorrect

Answer 6

6923 m. thats what i got