Question

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Answer 1

A train starts from rest moves with a constant acceleration of 2m/s^2 for half a minute. The brakes are then applied and then train comes to rest in one minute after applying breaks.
Find (a)The total distance moved by the train,
(b)the maximum speed attained by the train and
(c) the position(s) of the train at half the maximum speed

Answer 2

It can be solved into two parts.

Answer 3

\(\huge\sf Part-1\)
take u=0, a=2, t=1 and find s using second equation of motion, also find v using first equation.

Answer 4

ok

Answer 5

Part a)
half a minute is 30 seconds
ut+1/2at^2=s
0+1/2(2)(30)^2=s

Answer 6

Let @Abhisar only answer

Answer 7

Because it can get confusing

Answer 8

okay @No.name

Answer 9

yeahh he means let me do it first then u can answer @Abmon98 ...don't take it in other ways :)

Answer 10

S=ut+\(\frac{1}{2}\times2\times1^2\)

Answer 11

=1m

Answer 12

S = 1

Answer 13

Also from V=u+at, v= 2

Answer 14

Yes

Answer 15

Now the car will be deaccelarated...find a using v=u-at

Answer 16

take u=2 and v=0

Answer 17

t=1

Answer 18

u = 2?

Answer 19

yes, now find s using ut+\(\frac{1}{2}\times a\times t^2\)

Answer 20

How ?

Answer 21

u=2, t=1, a=2

Answer 22

oh yes

Answer 23

Finally add both the distances.

Answer 24

Thus total distance can be found out

Answer 25

Yes, first part over

Answer 26

Maximum speed

Answer 27

Max speed will be at the end of step 1......v=0+2\(\times\)1

Answer 28

(Well I answered your question)

Answer 29

I didn't get max speed

Answer 30

oh man !
There got a mistake...we took 1 min but 1/2 min was given.

Answer 31

But i got the idea its ok

Answer 32

How to find max speed

Answer 33

ok...u should also change minutes into seconds...1/2 min=30 seconds

Answer 34

(your question is answered) :)

Answer 35

yes..lets move to it....speed increases until body gets accelerated. Our car was accelerated until 30 seconds.

Answer 36

V=0+2*30=15m/s

Answer 37

oh so at 30th second velocity is maximum

Answer 38

yes

Answer 39

getting it ?

Answer 40

yes

Answer 41

the last part

Answer 42

at half the maximum speed,
V\(^2\)=U\(^2\)+2as, take u=0, v=7.5, a=2 and find s

Answer 43

okay i got it

Answer 44

sure ?

Answer 45

thank you , yes

Answer 46

\(\huge\sf\color{green}{\text{✌ﾟ\(\ddot\smile\) ✌ﾟ}}\)