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Geometry 13 Online
OpenStudy (anonymous):

https://media.glynlyon.com/g_geo_2013/5/tri1.gif a = 4 6 9

OpenStudy (anonymous):

Use Pythagoras Theorem: \(\Large c^2=6^2+4^2=52\) \(\Large (4+a)^2=c^2+b^2 \Rightarrow a=\sqrt{52+b^2}-4\) (1) \(\Large b^2=6^2+a^2 \Rightarrow a=\sqrt{b^2-36}\) (2) From (1)(2): \(\Large \sqrt{52+b^2}-4=\sqrt{b^2-36}\\\Large \sqrt{52+b^2}=\sqrt{b^2-36}+4\\\Large 52+b^2=b^2-36+8\sqrt{b^2-36}+16\\\Large\sqrt{b^2-36}=9\\\Large b^2=9^2+36=117\) \(\Large \Rightarrow a=\sqrt{117-36}=\sqrt{81}=9\)

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