PLEASE HELP A GIRL OUT The position of an object at time t is given by s(t) = -1 - 13t. Find the instantaneous velocity at t = 8 by finding the derivative.
take the derivative using the power rule and then sub 8 for t
s ' (8) is what you are looking for
Okay but how do I write that out?
do you know the power rule? It is the most basic rule for taking derivatives in calculus. It is the easiest one of all.
y=3x^2 y ' = 6x
oh okay. why did you use those numbers though?
just to give you an example of power rule y = x^2 y ' = 2x
Okay, but how do I find what x is?
for your solution you take the derivative ie s ' (t) and then sub 8 for t
example f(x) = x^2 and I want f ' (3) then f ' (x) = 2x f '(3) = 2(3) f'(3)=6
do you see what your solution is?
s′(t)=−13
right?
yes and guess what s ' (8)=-13 also, only because you don't have a variable to sub into
wait so this s ' (8)=-13 is all? There aren't any other steps?
@precal
no because we don't have a variable to sub into
so I can just write: s ' (t)=−13 s ' (8)=-13 or do I need to write it differently? @precal
the first one represents the first derivative of your function the second one represents the derivative at that particular time in this case t=8
go with the second one the first one is the velocity the second one is the velocity at that given time
Thanks :)
yw
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