Question

In the equilibrium system below, which of the following changes would cause the equilibrium position to shift to the right?

CO(g) + 3H2 (g)Two arrows stacked on top of each other. The top arrow points to the right. The bottom arrow points to the left.CH4 (g) + H2O (g) deltaH = -206 kJ/mol

Answer 1

decreasing the concentration of carbon monoxide (CO)

increasing the volume of the reaction system

decreasing the concentration of hydrogen gas (H2)

lowering the temperature of the reaction

Answer 2

According to Le Chatelier, the position of equilibrium will move so that the concentration of A increases again. That means that more CH4 and H2O will react to replace the A that has been removed. The position of equilibrium moves to the left. same thing when we decrease the concentration of H2

The equilibrium will move in such a way that the temperature increases again.The reaction will tend to heat itself up again to return to the original temperature. It can do that by favouring the exothermic reaction. more of CO and H2 are converted to CH4 and H2O and equilbrium will shift to the right.

Answer 3

so it would be lowering the temperature to where it increases again by itself? @Abmon98

Answer 4

exothermic means the release of energy, temperature increases but by lowering the temperature more products must be formed to retain its original temperature again

Answer 5

so would that be the answer? i'm confused :x

Answer 6

exothermic is +heat treat it as a chemical if we cool it were removing heat, if you take heat equilbrium would shift to the right to make more heat so the answer is lowering temperature....

Answer 7

okay sorry too many big words for my little mind :3 thanks for your help

Answer 8

you're welcome i will try making my explanation simpler :D