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you have 140 yards of fencing to enclose a rectangular region. find maximum area of rectangle
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let P = 140 yards = 2L + 2W, the perimeter P of the rectangle, L is the length, and W is the width of the rectangular region... the area A = LW...
140 = 2(L + W) 70 = L + W W = 70 - L eqn(1)
substitute W in area formula... A = LW = L(70 - L) = 70L - L^2 applying completing the square... L^2 - 70L + 1225 = -A + 1225 (L - 35)^2 = -A + 1225 Therefore the length L = 35 yards, the area A = 1225 sq. yards, then the width W = 70 - 35 = 35 yards... therefore the rectangular region is a SQUARE...
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