Help @thomaster
A car travelling at 72km/h decelerates uniformly at 2m/s^2. Calculate (a)the distance it goes before it stops (b)the time it takes to stop (c)the distance it travels during the first and third seconds
@Mashy
This is a trivial problem .. what are the initial data given?
Initial data?
to solve these problems.. u need the three equations of motion.. right? u know them?
yes yes
\[a(t)=-2\] There's one!
yea.. so like he said.. a = -2 m/s^2.. what else do u know?
Oh lol acceleration is -2km/h initial velocity = 72km/h
-2m/s^2 sorry
yea ok.. so u need to convert it into m/s.. do u know the final velocity? (the car comes to stop)
and converting that 72km/h into m/s gives 20
yea final velocity is 0
ok.. so u have u , v, and a can u calculate t and S ?
)the distance it goes BEFORE it stops means does it have any significance
BEFORE = distance travelled till it stops.. its just a way of speaking in english.. not any significance.. :)
Oh , then it's super-duper trivial
now that i think about it.. this is really genuine doubt.. which students can have.. and we teachers tend to over look thank you :).. i ll keep this in mind while teaching :) :). for next time
yes , teachers tend to overlook U a teacher??????
yup :D :D..
(c)the distance it travels during the first and third seconds what should we do for this distance travelled in 3 secons - distanc etravelled in 1 second
?
during first second distance travelled in first second = distance travelled in two seconds - distance travelled in 1 second in general.. distance travelled in nth second = distance travelled in total n seconds - distance travelled in (n-1) seconds
What is the difference , why can't we just take 1 second in our equation
1st second 2nd second or 3rd second.. all are 1 second time intervals.. so u need to know which 1 second interval we are talking about right?
but yea.. distance in 1 scond = distance in first second.. i agree but distance in 2 second is not equal to distance in 2nd second
Why
sry for trouble though
u teach where btw
u can think distance travelled in 2 seconds is.. total distance in 2 seconds interval but distance travelled in 2nd second is distance travelled in the 2nd 1 second ka time interval.. lets take simple example consider an object with zero speed.. and accelerates at 2m/s then in 1second it goes s = 1/2 at^2 = 1m in 2 second it goes s= 4m in 3 second it goes s = 9m in 4 second it goes s = 16 m.. and so on but.. now if i ask.. distance travlled in 2nd second.. it is 4 - 1 = 3m.. (this is the distance coverd by the object in 2nd 1 second interval) also distance in 3rd second = 9 - 4 = 5m.. (again.. this is distance travelled in the 3rd one second interval).. get it?
Oh i got the concept But if the question was , the particle is at what position at 3 rd second then the answer is 9m right
u can't say.. AT 3rd second cause 3rd second is an interval.. and in that interval.. the particle is travelling from 4m to 9 m.. so if u ask.. the position of the particle at the BEGINNING of 3rd second.. it is at 4m and at the END of 3rd second.. it is at 9 m
This is confusing but i get it btw where do u teach
ur a man
?
yea m a man :P.. i teach in mangalore..
grt , if u r searching for questions in physics http://manishkumarphysics.in/kota/?page_id=271
(b)the time it takes to stop? Do we use v=u+at
yes.. use that
thanks for the link.. is that ur site?
if that was my site i wouldn't have asked this question lol
that is for IIT preparation
haha lol.. ok xD
CAn we do the last part , i feel to discuss it
@Mashy
yes.. calculate..
i am not getting just the last part
fist second . u put t = 1 right? for third second find distance in 3 second, distance in 2 second.. then subtract
yes i made a math error
:P
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