Find the length of c if a=62 degrees and angle b =39 degrees and b = 15.
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OpenStudy (imstuck):
is 62 an angle measure?
OpenStudy (undeaddragon26):
yea
OpenStudy (imstuck):
ok I got you...let me set it up.
OpenStudy (imstuck):
First thing you need is the measure of angle C. You can find that by subtracting 39 and 62 from 180. The difference is C.
OpenStudy (undeaddragon26):
79
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OpenStudy (imstuck):
Angle C is...79, right!
OpenStudy (undeaddragon26):
yea
OpenStudy (imstuck):
Now you need to tell me that you are familiar with the Law of Sines
OpenStudy (undeaddragon26):
sorta im a little rusty
OpenStudy (imstuck):
Ok, it looks like this:
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OpenStudy (imstuck):
\[\frac{ sinA }{ a }=\frac{ sinB }{ b}=\frac{ sinC }{ c }\]There are 2 things you need to know about this: the lowercase letters are side lengths while the uppercase are angles, and you only need two of those identities to solve for either a missing length or missing side.
OpenStudy (imstuck):
You have angle B and the side length of b, you also have angle C now and you want side c. So that gets set up like this:
OpenStudy (imstuck):
\[\frac{ sinB }{ b}=\frac{ sinC }{ c }\]and you have three of the 4 of those needed. You have this:\[\frac{ \sin(39) }{ 15 }=\frac{ \sin(79) }{ c }\]
OpenStudy (imstuck):
To solve for side c you will cross multiply. Can you do that?
OpenStudy (undeaddragon26):
1185=39c
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