Please Help, Create a rational function with a linear binomial in both the numerator and denominator. Part 1. Graph your function using technology. Include the horizontal and vertical asymptotes and the x- and y-intercepts on your graph. Label the asymptotes and intercepts. Part 2. Show all work to identify the vertical asymptote, the x-intercepts, and the y-intercept.
Rational function looks like a fraction. Linear binomial is something like (x-2). You want similar terms in both the numerator and the denominator, so it might look like\[f(x)=\frac{x-a}{x-b}\]Pick numbers for a and b, and you are on your way.
does it matter which numbers I pick
Nope, as long as they aren't zero, or the same as one another.
ok so a=3 b=5
I recommend easy numbers: small integers.
Yeah, that will work.
ok so I would just graph those and then how would I figure out part 2
Well, the vertical asymptote is at the undefined value of x. Can you tell me what that is?
im not really sure im like confused
Well, is there any number that is excluded from the domain?
We aren't allowed to divide by zero, so any number that makes the denominator of the function zero can't be in the domain. What value of x would that be?
um im not really sure would it be like 5
Exactly. That means x=5 is the vertical asymptote. Now, how do we find the x intercept?
If the function is intercepting the x axis, what is the y value?
ok well I graphed \[f(x)=\frac{ x-3 }{ x-5 }\] and got 3 as the x intercept
Correct. To do it algebraically, you set y (keeping in mind that y = f(x)) to be zero. That will allow you to get that solution. Good. Two down, one to go. How do we find the y intercept?
do you set x=0
Yep.
so would the y intercept be 0.6
Looks like you've got it. Nice work. Do math every day.
lol thank you so much this really helped me a lot
No sweat. Do math every day.
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