Question

Write an equation of a line parallel to y = 2/3x −5 in slope-intercept form that passes through the point (−6, −1).

Answer 1

do you have a graph of that equation?

Answer 2

Theres no graph but it has these answers
y= 2/3x+3

y=2/3x+6

y= -3x-1

y=3x+6

Answer 3

You know the slope is going to be 2/3 because it is parallel to the other line. Since you only have one point of the parallel line you need to first right it in point-slope form.
Point-slope equation:y - y1 = m(x - x1)
So for the parallel line this would y- (-1) = 2/3 (x- (-6))
can you transform this equation into slope- intercept?

Answer 4

i know slope intercept form is y=mx+b but how would you change that to slope intercept?

Answer 5

hello first thing for the equation that is .It is parallel to the given equation
so the slope of both equations should be same
m1=m2
the slope of given equation is 2\3
m1=2\3
so m2 = 2\3
now use the point slope form and put the slope and given point in it
(y- y1)=m(x -x1)
y-(-1)=2\3(x-(-6))
y+1 = 2\3 (x + 6)
3(y+1) = 2(x+6)
3y+3 =2x+12
3y=2x+12 -3
3y=2x+9
for making slope intercept form put 3 on the other side
y=2\3 x + 3
this is the correct answer

Answer 6

First you want to simplify the equation so it would look like:
y+1= 2/3 (x+6) distribute the 2/3:
y+1= 2/3x + 4 you want to get y alone so subtract 1 from that side
y = 2/3x + 3
so the answer is a!

Answer 7

Thank you so much!

Answer 8

No problem good luck with the rest of your assignment! :)