Solve the following system using the graphing method:
y = -x + 2
y = x + 4
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OpenStudy (anonymous):
@aum
OpenStudy (anonymous):
OpenStudy (anonymous):
OpenStudy (anonymous):
@IMStuck PICS ATTATCHED
OpenStudy (anonymous):
@zaibali.qasmi
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OpenStudy (imstuck):
I'm here. sorry it took so long.
OpenStudy (anonymous):
its ok
OpenStudy (imstuck):
the solution to this system is where on the graph the lines cross each other. So you need to decide which graph depicts your given lines. Do you know how to determine a graph from an equation in the form y = mx + b?
OpenStudy (anonymous):
not really I have pics attathed by the way
OpenStudy (anonymous):
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OpenStudy (imstuck):
it's the last graph on pic_21.jpg
OpenStudy (imstuck):
not the one you just attached. Its the other one, the second graph on that second page.
OpenStudy (anonymous):
ok thank :)
OpenStudy (anonymous):
how about this one
OpenStudy (anonymous):
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OpenStudy (anonymous):
@IMStuck
OpenStudy (imstuck):
is the system
y = -4x + 1 and
-12x + 3y = 3
OpenStudy (anonymous):
no y-4x+1
-12x+3y-3
OpenStudy (imstuck):
oh that changes everything!
OpenStudy (anonymous):
lol
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OpenStudy (imstuck):
There are no equal signs in those!!!???
OpenStudy (anonymous):
none
OpenStudy (imstuck):
give me a sec then, ok?
OpenStudy (anonymous):
ok
OpenStudy (imstuck):
in my experience you have to have a y = something line in order to graph. From what I can tell about those lines is that it is the second choice down on the image you posted.
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OpenStudy (anonymous):
b?
OpenStudy (aum):
Without equal signs, there are no equations.
OpenStudy (anonymous):
is there a graphingcalculator I can use
OpenStudy (aum):
It is a small print but I think the equations are:
y = 4x + 1 (not y minus 4x but y equals 4x + 1)
-12x + 3y = 3 (not minus 3 but equal to 3)
OpenStudy (anonymous):
y = 2x + 1
-4x + 2y = 4 would this be inconsistent?
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OpenStudy (aum):
y = 4x + 1
-12x + 3y = 3
Take the second equation and solve for y.
-12x + 3y = 3
add 12x
3y = 12x + 3
divide by 3
y = 4x + 1
The second equation is identical to the first equation!
Since both equations are the same they are consistent and dependent.
In the graph the two equations will show up as one single line with a positive slope of 4.
OpenStudy (anonymous):
ok so both are consistent
OpenStudy (aum):
consistent
and
dependent
OpenStudy (anonymous):
does it look like this @aum
OpenStudy (aum):
look like what?
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OpenStudy (anonymous):
OpenStudy (anonymous):
@aum
OpenStudy (anonymous):
?????
OpenStudy (aum):
No. Both equations are the same: y = 4x + 1.
So if you plot them there will be just one line.
And slope m = 4. So it should have a positive slope.
OpenStudy (anonymous):
all of my choices have two lines
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