when tossing 4 coins simultaneously , find the probability that at least 1 head is showing .
Are you familiar with probability trees?
no not really ! @mathmate
Do you have any suggestions how to solve the problem?
The probability of getting tails for a given coin toss is (1/2). So for four coin tosses it is (1/2)^4. Thus: P(all 4 tails) = (1/2)*(1/2)*(1/2)*(1/2) = (1/2)^4 = 1/16 Hence: P(atleast one head) = 1 - P(all tails) = 1 - 1/16 = 15/16
@anna113 @nurali has solved it exactly how I would have solved the problem, athough I may not have explained it the same way. I suggest you follow up with nurali if you need further explanations.
thanks @mathmate and @Nurali
Anytime.
You're welcome! Don't forget to give a medal to nurali! :)
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