Question

The height of the regular hexagon shown is 24 in. Calculate the area to the nearest tenth.
http://media.education2020.com/evresources/2092290_6d171c38-23d5-49e0-81c1-9a0b94965f3c.png

A.
152.7 in.
B.
432.0 in.
C.
498.8 in.
D.
997.7 in.

Answer 1

Well, do you know the equation to find the area of a hexagon if you know the apothem?
Because the apothem would be 1/2 the of 24. :)

Answer 2

Oh yeah and I forgot that each of the answers has a ^2 after the in.

Answer 3

for i don't understend the meaning behind tenth, but i might give you answer for surface of hexigon:
for sum of all corners in degrees use formula 180*(n-2) when n is number of corners, leaving you with 720 degrees in total, meaning 720/6 is degrees of one corner (120).
next what you do is sligthly move that 24 in line to side with your imagination :) so that it forms triangle with two sidelines of hexagon. Given that for hexagon to form all six side lines of it must be of same lenght you name have something familiar to my drawing
now you can count degrees of formed corners by knowing that b is equal to 120 degrees by rule and a is equal to 30. Now use given formula that x^2 = d^2 + x^2 - x*d*cos(b) from wich you find that x is equal to x^2 - x^2 +x*d*cos(b) = d^2 so x*d*cos(b)=d^2 and since yu have d as 24 and b as30 you get 24*x*cos(30)= 24^2 making it x*cos(30)=24 so in the end you have x= 24/ cos(30)
since you have the lenght of all three sides of that lil triangle and both lenghts of big square you can count area of hexagon as square +2 times triangle area, i hope this helps, sorry for poor english