Question

I Really Need Help!!!
The molar mass of Fe(OH)3 is 106.87 g/mol. How many moles of H2SO4 are needed to react completely with 5.419 g of Fe(OH)3?
2Fe(OH)3 + 3H2SO4 --> Fe2(SO4)3 + 6H2O

Answer 1

find mole of Fe(OH)3
mole= mass/molar mass
you are given both mass and molar mass
so put the values into this formula and get the answer for mole

now u found mole of Fe(OH)3

so now you can use this formula
\[\frac{ mole~of~Fe(OH)_3 }{ coefficient~of~Fe(OH)_3} =\frac{ mole~of~H_2SO_4 }{ coefficient~of~H_2SO_4 }\]

you know mole of Fe(OH)3 and you know both coefficients of H2SO4 and Fe(OH)3 so now you can find mole of H2SO4 by cross multiplying

hope it helps :)

Answer 2

I'm sure they will say it is too much

Answer 3

who will say @kametri7 ?

Answer 4

An administrator. I didn't mean to but I was posting the answers by mistake.

Answer 5

idk why but im not getting u <.< what does admin have to do with this question ?

Answer 6

I meant that I may have showed too much. I wanted to show the person how to set up the problem. I am not sure if I went too far. That's all. I'm new at this.

Answer 7

ohhh i see :)
don't worry
you should show the steps thats it
make the question clear and explain how to do it
no direct answers should be given
as well as no FULL working should be given
basically u can do part of the work to make it clear
but u should leave some work for the asker
:)

Answer 8

Got it. Thanks!