find the coordinate of point p which divides the line segment a=(0,4) to b=(6,8) in a ratio of 1:2
over 6 up 4 maybe over two up oh dang
over two up \(\frac{4}{3}\) ?
ok i probably screwed that up let me think for a second
well actually maybe that is right what method are you supposed to use ?
i would try \[(2,5\tfrac{1}{3})\] and see if that works
I'm supposed to use the directed line segment formula i think
x = 0 + 1/3 * (6-0) y = 4 + 1/3 * (8-4)
i wish i knew that that was maybe @aum will know
looks like what i wrote had no idea that was a formula!!
tbh idek what it is ... the answer was right though so thanks(:
yw
They want a point 1/3 of ab from a. The x-coordinate will be 1/3 along the "x distance" from a. The y-coordinate will be 1/3 along the "y distance" from a.
|dw:1405475055221:dw| IF AC is 1/3 of AB, then, due to similar triangles: AD = 1/3 * AE = 1/3 * (x2-x1) CD = 1/3 * BE = 1/3 * (y2-y1) x coordinate of C = x1 + 1/3 * (x2-x1) y coordinate of C = y1 + 1/3 * (y2-y1)
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