Question

equation of tangent line to y=xcosx at x = pi

Answer 1

substitute pi into equation and got y1 = 0

Answer 2

f ' (x) = cosx + x - sinx

Answer 3

which slope equals -pi

Answer 4

y-0 = -pi(x-pi) ?

Answer 5

f'(x) = cos(x) + -xsin(x) I believe

Answer 6

no its not.

Answer 7

i thought so too but according to mathway.com its cosx - sinx

Answer 8

Your slope is -1.

Answer 9

can you show me how ?

Answer 10

cos(pi) =-1 sin (pi)=0 thus -1 +0 = -1

Answer 11

its -xsinx

Answer 12

-x sinx same thing would be pi times sin(x) or pi times 0.

Answer 13

oh right.

Answer 14

okay so for the equation

Answer 15

y1 = 0 right ?

Answer 16

y-xcosx= 1(x-pi) Now solve for y.

Answer 17

its negative 1 not positive 1

Answer 18

Right

Answer 19

so is it-1 - pi ?

Answer 20

y-xcos(x)=-1(x-pi) Solve for y.

Answer 21

y = -x ?

Answer 22

OK solve the right side of the equation first. -1(x-pi) = what>