Consider the equation below. e^5x+e^-x (b) Find the local minimum value of f. (c) Find the interval on which f is concave up. (Enter your answer using interval notation.)
noted
Arrange the variables alphabetically within the expression A5x. This is the standard way of writing an expression. xe5+e−x
is that right @satellite73
@satellite73 i put more infor to solve
You have to find the first derivative and the second derivative of the function first. Setting the first derivative to zero gives you the global extrema (minimum or maximum point). The second derivative gives you information on whether the function concaves up or down at a particular point. When it concaves up, the value is positive, and when it concaves down, the value is negative. Use values a little to the left and right of the extremas to determine the interval for which the function concaves up. Tip: plotting the graph will help too!
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