Question

balanced complete ionic and net ionic equations
HClO4(aq)+Ca(OH)2(aq)→
this is what i got but its wrong H+(aq)+SO32−(aq)→SO2(g)+H2O(l)

H2SO4(aq)+Li2SO3(aq)→
H+(aq)+SO42−(aq)+2Li+(aq)+SO32−(aq)→2Li+(aq)+SO42−(aq)+SO2(g)+H2O(l)

Answer 1

HCLO4(aq)+Ca(OH)2-->Ca(ClO4)2+H2O
Double Displace occurs Calcium goes with perchlorate ion, Calcium has a charge of +2 and Perchlorate of -1 Interchange Charges to form Ca(ClO4)2 H goes with OH to Form H2O
Balance Chemical equation
Write down the number of atoms that you have on each side of the equation.
On the reactant side: 3 H, 1 Cl, 6 O and 1 Ca
On the product side: 2 H, 2 Cl, 9 O and 1 Ca
Add a coefficient of HCLO4 to balance Cl
2HCLO4(aq)+Ca(OH)2-->Ca(ClO4)2+H2O
On the reactant side: 4 H, 2 Cl, 10 O and 1 Ca
On the product side: 2 H, 2 Cl, 9 O and 1 Ca
Add a coeffcient of 2 to H2O to balance H
2HCLO4(aq)+Ca(OH)2-->Ca(ClO4)2+2H2O
On the reactant side: 4 H, 2 Cl, 10 O and 1 Ca
On the product side: 2 H, 2 Cl, 10 O and 1 Ca

To get the total ionic equation we break all our aqueous molecule into their constituent
ions
2H+(aq) +2CLO4-(aq)+Ca+2(aq)+2OH-(aq)--->Ca+2(aq)+2CLO4-aq)+2H+(l)+2OH-(l)
Cross out ions on both side (spectator ions)
2H+(aq)+2OH-(aq)-->2H+(l)+2OH-(l)