find dy/dx for the equation xsiny=1

Question

anonymous · Answer

@song6  I am sorry, I am not with you then. :)

anonymous · Answer

xsiny=1--> siny = 1/x--> y = arcsin(1/x), then take derivative and apply chain rule to get y' = (arcsin(1/x)' = we have formula to get this derivative, right??

neer2890 · Answer

x siny=1
$$siny=\frac{ 1 }{ x }$$
$$cosy \frac{ dy }{ dx }= \frac{ -1 }{ x ^{2} }$$

anonymous · Answer

At the end, you still have cos y which is unknown. How?? You must find out y' w.r.t x only.

anonymous · Answer

attachment

anonymous · Answer

$$y' = (arcsin(1/x)' = \dfrac{1}{\sqrt{1-(1/x)^2}}*(1/x)'=-\dfrac{1}{x^2\sqrt{1-1/x^2)}}$$

anonymous · Answer

y' totally respects to x, you don't have any y from the right hand side.

anonymous · Answer

um ...wait for a second

anonymous · Answer

http://www.wolframalpha.com/input/?i=%28arcsin%281%2Fx%29%29%27

anonymous · Answer

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