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Mathematics 8 Online
OpenStudy (anonymous):

please help! Suppose that F(x) = 3x and G(x) =5/x-6. Which statement best explains why x = 2 is not in the domain of G(F(x))? (picture) https://fbcdn-sphotos-e-a.akamaihd.net/hphotos-ak-xpa1/t1.0-9/p180x540/10501717_813210652032205_900232893868592867_n.jpg

OpenStudy (sidsiddhartha):

have u calculated G[F(x)]?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

i don't know how to do that. that's why i'm asking.

OpenStudy (sidsiddhartha):

first\[g[f(x)]=g[3x]\] agree?

OpenStudy (sidsiddhartha):

just substituting F(x)=3x

OpenStudy (anonymous):

what's the result ?

OpenStudy (sidsiddhartha):

now given \[g(x)=\frac{ 5 }{ x-6 }\] so when u are calculating g(3x) then u just have to substitute 3x in place of x \[g(3x)=\frac{ 5 }{ 3x-6 }\] ok got that?

OpenStudy (sidsiddhartha):

so if u substitute x=2 in G[f(x)] it will have a zero denominator so the function will be undeifned so what do u think is the correct option?

OpenStudy (anonymous):

@sidsiddhartha A?

OpenStudy (sidsiddhartha):

yeah A ^_^

OpenStudy (anonymous):

thank you! ;)

OpenStudy (sidsiddhartha):

no pro buddy :)

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