Question

Can someone help me factor 5y^3+10y^2-4y-8
using the grouping method?

Answer 1

Please I really need help

Answer 2

Let's try ;)
\[5y^3+10y^2-4y-8\]\[5y^2*(y+2)-4*(y+2)\]the answer is:\[(y+2)*(5y^2-4)\]

Answer 3

Why y+2?? I'm confused

Answer 4

\[5y^2*(y+2)=5y^3+10y^2\]and\[-4*(y+2)=-4y-8\]You have to use the signal rule

Answer 5

Ohhh okay factoring them both gives you y+2, then what?

Answer 6

you can factoring again because (y+2) is common in both members

Answer 7

okay so 5y^2(y+2)+-4(y+2)? Or how is it written out exactly?

Answer 8

@D3xt3R ?

Answer 9

\[5y^2*(y+2)-4*(y+2)\]\[(5y^2-4)*(y+2)\]

Answer 10

Okay, so with the commutative property of multiplication we can rewrite it as (y+2)(5y^2-4) yes?

Answer 11

Exactly