Question

calculate the energy released when a 28.9 gram piece of copper is cooled from its melting of 1083 C to 25.0 C. The specific heat of copper is .385 J/g C

Answer 1

E = m × c × θ
E is the energy transferred in joules, J
m is the mass of the substances in kg
c is the specific heat capacity in J / kg °C
θ (‘theta’) is the temperature change in degrees Celsius, °C (Final Temp-Intial Temp)
E=28.9*0.385*(25-1083)

Answer 2

@Abmon98 i think it's time you learn some \(\LaTeX \)