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Mathematics 17 Online
OpenStudy (anonymous):

X^(1/x) x>0 Explain the shape of the graph by computing the limit as x → 0+ and as x → ∞.

OpenStudy (cwrw238):

as x approaches positive infinity what does 1 / x approach?

OpenStudy (anonymous):

negative infinity

OpenStudy (anonymous):

0 i mean

OpenStudy (cwrw238):

no think about values like 1/100 , 1/1000, 1/1000000 , 1 / 1000000000 etc what do these get close to?

OpenStudy (anonymous):

0

OpenStudy (cwrw238):

right now how about x^0 - what does that equal?

OpenStudy (anonymous):

1

OpenStudy (cwrw238):

exactly, so as x--> infinity the graph approaches 1 and will look a horizontal line at f(x) = 1 In mathematical terms there will be an asynptote at f(x)= 1

OpenStudy (cwrw238):

as x approaches 0 from above what happens to 1/x ?

OpenStudy (anonymous):

it gets bigger approaches infinity

OpenStudy (cwrw238):

yes - eg when x = o.001 for example 1/x = 1000 but as x is small then x^(1/x) will also be small note when x = 1 f(x) = 1

OpenStudy (anonymous):

it gets smaller

OpenStudy (cwrw238):

graph will look something like |dw:1405530854195:dw|

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