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Mathematics 19 Online
OpenStudy (anonymous):

Factor completely. 10x3 + 2x2 + 5x + 1 (2x2 + 1)(x + 1) (2x2 + 1)(5x + 1) (5x2 + 1)(x + 1) (5x2 + 2)(5x + 1) CAN SOMEONE PLEASE HELP ME WITH THIS PROBLEM

OpenStudy (akashdeepdeb):

\[10x^3 + 2x^2 + 5x + 1\] Try to find 2 pairs of 2 terms which give something common. \[2x^2(5x + 1) + 1(5x+1)\] \[(5x+1)\] is common, use the reverse of the distributive property now. Group the together. Here's what i mean: \[2x^2(5x + 1) + 1(5x+1)\] \[(5x+1)(2x^2 + 1)\] Getting this? :)

OpenStudy (anonymous):

Not really its confusing

OpenStudy (akashdeepdeb):

ab + ac How do you factorize that?

OpenStudy (akashdeepdeb):

@melani21 ?

OpenStudy (anonymous):

i have no clue

OpenStudy (anonymous):

@AkashdeepDeb Factor completely. 20x3 + 12x2 + 5x + 3 (2x2 + 1)(5x + 3) (2x2 + 3)(5x + 3) (4x2 + 1)(x + 3) (4x2 + 1)(5x + 3)

OpenStudy (akashdeepdeb):

What does factorization actually mean? It means I have to write everything in the form of products/multiples. ab + ac Is this in the form of products? No. It is not. It is a sum. How do we turn it into a product? Well, I can take something common [see the 'a'?] and write it in that form. ab + ac = a times (b+c) = a * (b+c) Isn't that cool? We just wrote it as a product! Can you try writing \[x^2 + 2x\] in the factorized form?

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