Question

how to change an equation from vertex to standard form

Answer 1

well vertex form can be

\[y = (x - h)^2 + k\]

just distribute (x - h)^2 then collect like terms

Answer 2

The Standard Form for a linear equation in two variables, x and y, is usually given as
Ax + By = C
where, if at all possible, A, B, and C are integers, and A is non-negative, and, A, B, and C have no common factors other than 1. If we have a linear equation in slope-intercept form,
y = m x + b
we can change that equation into Standard Form. To do this we need to express the slope and the ordinate of the the y-intercept in rational number form, that is, as the quotient of two integers. For the kinds of problems that we usually find in math classes, this is not much of a demand. The slope is defined to be the change in y divided by the change in x. Thus, if we express the slope as ychange/xchange, we will have met our first demand. The ordinate of the y-intercept usually follows the same scheme, so we can express that value, the "b" in y=mx+b, as the quotient of two integers, which we will call b_num and b_den. This means that our slope-intercept form
y = m x + b
can be rewritten as
y = (ychange/xchange) x + b_num/b_den
If we multiply both sides of the equation by the least common multiple of xchange" and "b_den", the resulting equation will have no fractions. It will appear as
Dy = Ex + F
where D, E, and F are integers. Then, we add – Ex to both sides of the equations to get – Ex + Dy = F To get this into standard form we want the coefficient of x to be non-negative. If – E is actually negative, then we can multiply both sides of the equation be – 1. In either case, we end up with an equation that has the standard form,
Ax + By = C

Answer 3

and i got that from the site: http://courses.wccnet.edu/~palay/precalc/22mt01.htm

Answer 4

the only problem @Prestianne vertex form applies to quadratic equations... and not linear equations... and you copy and paste refers to.

Answer 5

aww :( sry then. but you can always use to uderstand and see if you can apply the information

Answer 6

ok so all i need to do is distribute (x - h)^2 then collect like terms? i thought you had to use foil or something?

Answer 7

well you need foil to handle (x -h)^2 as its (x -h)(x - h)

Answer 8

oh ok so using foil = (x -h)^2 ?