Question

A segment with endpoints I (5, 2) and J (9, 10) is divided by a point K such that IK and IJ form a 2:3 ratio. Find the y value for K.

4.6

5.4

4.8

5.2

Answer 1

i need some help pronto

Answer 2

@aum

Answer 3

@phi

Answer 4

@gswag98

Answer 5

im not good at this

Answer 6

@campbell_st

Answer 7

@AkashdeepDeb do you know how to do this?

Answer 8

c

Answer 9

how did you get that melani?

Answer 10

i dont understand at all

Answer 11

Baahh! i was going to type an answer and I refreshed the page.

This is known as internal division.
The point k divides the line into 5 parts. 2 parts with one side and 3 parts with the other.

Check this link: It explains it well: http://www.teacherschoice.com.au/Maths_Library/Analytical%20Geometry/AnalGeom_3.htm

Answer 12

@AkashdeepDeb could you use the formula and show me how i would find it idk how to use that

Answer 13

that formula is really hard for me

Answer 14

im not asking for an answer just if you could plug in the numbers in the equation for me

Answer 15

find the difference (in the y values) from point I to point J

divide that difference by 5

Answer 16

multiply by 2
add that to the starting y value (the y value of point I)

Answer 17

No problem. It is very simple. Here is a general example.

\[(x,y) = (\frac{mx_2 + nx_1}{m+n},\frac{my_2 + ny_1}{m+n})\]
\[x = \frac{mx_2+nx_1}{m+n}\]\[y = \frac{my_2 + ny_1}{m+n}\]

Basically, the x value of the point dividing the line uses the x values of the 2 end points.
And the y value of the point dividing the line uses the y values of the 2 end points.

Getting this? :)

Answer 18

this is hard im only in tenth man and i failed geometry

Answer 19

@AkashdeepDeb

Answer 20

is there a simpler way idk how to do this man its really confusing

Answer 21

ive never been taught on how to use that

Answer 22

I understand. Don't be overwhelmed by what i wrote up there. You most probably would understand it in a few months, when you may do it in school. I am not really aware of any other method. [Other than graphing it or using the formula I wrote above].

But there is always another way. Try tagging someone else, who you think could help. :)