I need HELP! I'm posting a picture on a reply with this but it has to do with writing equations!
This is it!^
for each of the edges of the shape you can constrauct a right angle triangle :|dw:1405543155899:dw| I have drawn 1 of them You can get the lengths of the dotted sides from the points (y2-y1, and x2-x1) So then you can use Pythagoras to calculate ethe length of the side of the shape (the hypotenuse of the triangle) Each side will have a different solution, but all use the same method. Then add up the 4 sides to get the perimeter of the shape
Will you calculate that one side for me using the formula. Not sure how to start the equation.
|dw:1405543555360:dw| What is the length of the line I have drawn (use the points from your original drawing)
I'm not sure. I'm new to this!
I am not going to give you the answer - if oyu want to work with me on this then do so... LOOK at your original drwing - it gives the coordinates for the 4 points. The line I drew in Black above is the difference in y between point M and N It is not difficult to deduce that from the drawing - take a look at it, and then tell me the length of the line I drew
0? because the difference in why which the two why points were 1 and -1 so the difference would be 0
what is 1 minus (minus 1) ?
*y not why
oh i forgot to keep change change. so 2
OK (also - it is pobvious that the line is not 0 length!) Now do the same for the length of the horizontal line (difference in x)
-4?
Well - lengths do not really come in - numbers - you can do x2-x1 the answer is 4 |dw:1405544366538:dw| So now you have a right angle triangle - you know the 2 short sides so use a^2+b^2=c^2 to calculate l in my drawing
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