Question

How many grams of Na2CO3 are required to make 0.100 moles of Na2CO3? @Abmon98

Answer 1

Number of Moles=Mass(g)/Molar Mass(g/mol)
Look at your periodic table for each element atomic weight in Na2CO3
Na: 23 gram C: 12 gram O: 16 gram
Molar Mass(g/mol)=(23*2)+(12*1)+(16*3)=88 gram
Number of Moles=Mass(g)/Molar Mass(g/mol) Rearrange your equation
Mass(g)=Molar Mass(g/mol)*Number of Moles
Mass(g)=0.100*88=8.8

Answer 2

Thanks For explain

And in thatn How many actual molecules of methane are present in 32 grams of methane?

Answer 3

methane molar mass is 16
12+(1*4)=16 use number of moles=mass(g)/molar mass(g/mol) plug in you given mass
32/16= 2 mole of methane
1 mole consists of 6.02*10^23 molecules (Avogadro constant number)
2 moles consist of x molecules
x=2*6.02*10^23/1 molecule

Answer 4

mole= mass/Molecular mass
u have mass as 32g and molecular mass of Methane u can find from periodic table

after you found mole - multiply it by Avogadro number which is \(6.02 \times 10^23\)

Answer 5

so the answer is 19,264,000 or not?

Answer 6

no you calculated it wrong

Answer 7

put ( \(6.02 \times 10^23\) ) in brackets like this and the multiply by 2