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OpenStudy (superhelp101):
How many moles of LiOH are required to prepare 1.50 L of 5.4 M LiOH? 0.28 mol LiOH 3.6 mol LiOH 6.9 mol LiOH 8.1 mol LiOH @Abhisar how would i solve this?
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OpenStudy (somy):
molarity= mole/volume mole= molarity* volume
OpenStudy (somy):
put the values into the formula and get the answer
OpenStudy (superhelp101):
is this the volume 1.50 ?
OpenStudy (abmon98):
Yes @superhelp101
OpenStudy (somy):
thats right :)
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OpenStudy (superhelp101):
Cool. Thank y'all
OpenStudy (somy):
np :)
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