Question

Solve the following system using the elimination method:
6x - 2y = 4
-2x + 4y = 12

Answer 1

@zepdrix

Answer 2

hi c:

Answer 3

hey!

Answer 4

To eliminate, we need to have the `same` coefficient on one of our variables.

Answer 5

To to match up our x's, we would want a 6 in front of each.
How could we fix up the second equation to make that happen?

Answer 6

hmmm

Answer 7

not sure

Answer 8

Hmm it currently has a value of -2.
Let's multiply it the second equation by 3 and see what happens.
(We're multiplying both sides by 3, otherwise things become unbalanced).\[\Large\rm 3(-2x + 4y) = (12)3\]Distributing the 3 gives us,\[\Large\rm -6x + 12y =36\]

Answer 9

Now our system is,\[\Large\rm 6x - 2y = 4\]\[\Large\rm -6x + 12y =36\]

Answer 10

The reason we're doing this is so that we can either add or subtract our equations together, and hopefully one of the variables will cancel out.

Answer 11

(0,3) (1, 7/2)

Answer 12

inconsistent

Answer 13

? =o

Answer 14

I calculated it Im wrong I guess??

Answer 15

I don't know what you did...

Answer 16

Since our equations have `opposite signs` on the x's, we'll want to `add` them together.

Answer 17

So 6x and -6x add to zero.
And we're left with:\[\Large\rm 10y=40\]

Answer 18

4