Question

Help please

Answer 1

Pic

Answer 2

@phi

Answer 3

For any radical function, you'll have

\[y=a*\sqrt{x-b} +c\]

So, c modifies directly the "y" value, as you should know an square root is always

\[\sqrt{k} \ge 0 \]

So, as your minimum y value is -1 , c=-1

Now, b modifies the value for the zero of your square root
And you have
\[\sqrt{x-b} = y+1\]
For y=0

\[\sqrt{x-b}=1\]

According to your graphic y=0 -> x=-1
So replacing
\[\sqrt{-1-b} = 1\]

The only way to get a square root of 1 is

\[-1-b=1\]
therefore b=-2

and your function will be

\[y=\sqrt{x+2} -1\]