Mathematics
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OpenStudy (anonymous):
If the area of a circle is 8pi, what is the length of it's diameter?
Will fan/medal:)
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jimthompson5910 (jim_thompson5910):
\[\Large A = \pi*r^2\]
\[\Large 8\pi = \pi*r^2\]
\[\Large r = ???\]
OpenStudy (anonymous):
I've tried that I just can't seem to figure out the first step I need to take!
jimthompson5910 (jim_thompson5910):
how do you get r^2 all by itself
OpenStudy (anonymous):
Somehow get rid of the pi, but I'm not sure how to?
jimthompson5910 (jim_thompson5910):
why not divide both sides by pi
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OpenStudy (anonymous):
I will try that
jimthompson5910 (jim_thompson5910):
that will get rid of pi on both sides
because pi/pi = 1
jimthompson5910 (jim_thompson5910):
after r^2 is isolated
you have to isolate r itself
OpenStudy (anonymous):
so square root r^2?
jimthompson5910 (jim_thompson5910):
square root both sides
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OpenStudy (anonymous):
I got 2.8284721=r, but the only answer choices I have are
a. 4
b. 8
c. \[2\sqrt{2}\]
d. \[4\sqrt{2}\]
OpenStudy (anonymous):
I don't know if I have to convert to a radical.. If so, I don't know how to.
jimthompson5910 (jim_thompson5910):
Simplify \[\Large \sqrt{8}\]
OpenStudy (anonymous):
\[2\sqrt{4}?\]
OpenStudy (anonymous):
vice versa
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jimthompson5910 (jim_thompson5910):
\[\Large \sqrt{8} = \sqrt{4*2} = ???\]
OpenStudy (anonymous):
\[4\sqrt{2}\] i mixed it up on accident
jimthompson5910 (jim_thompson5910):
\[\Large \sqrt{8} = \sqrt{4*2} = \sqrt{4}*\sqrt{2} = ???\]
OpenStudy (anonymous):
\[2\sqrt{2}\]
jimthompson5910 (jim_thompson5910):
That's the radius
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jimthompson5910 (jim_thompson5910):
We want the diameter
jimthompson5910 (jim_thompson5910):
\[\Large r = 2\sqrt{2}\]
\[\Large d = ???\]
OpenStudy (anonymous):
urggg. so its not \[4\sqrt{2}\]
jimthompson5910 (jim_thompson5910):
it is, I'm getting there
jimthompson5910 (jim_thompson5910):
I want to make sure you know how to get there
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OpenStudy (anonymous):
Okay, I've never been good at radicals.. Sorry!
jimthompson5910 (jim_thompson5910):
that's ok, just keep practicing and you'll get better
OpenStudy (anonymous):
Yeah I just need A LOT of practice :) But you explain things to me very well!
jimthompson5910 (jim_thompson5910):
Glad some of it is starting to make sense
OpenStudy (anonymous):
Me too, trust me.. :)