Question

PLEASE HELP WITH A FEW GEOMETRY QUESTIONS! MEDALS WILL BE GIVEN AND I WILL BECOME A FAN!!

1.)The figure below shows two triangles EFG and KLM.Which step can be used to prove that triangle EFG is also a right triangle?
A.) Prove that the sum of a and c is greater than b.

B.) Prove that the sum of a and b is greater than c.

C.) Prove that triangles are congruent by SSS property and hence, angle EGF is equal to angle KML.

D.) Prove that the ratio of EF and KL is greater than 1 and hence, the triangles are similar by AA postulate.

Answer 1

@ninjasandtigers ?
@ShortyB?

Answer 2

can i see the image?

Answer 3

yea gimme a sec

Answer 4

c, because you know that two sides are similar and that means the third side is similar and if one triangle has a right angle, the other one would too

Answer 5

Ok thanks. I have a few more questions. Some I think I know the answers to. Mind helping me out a little more?

Answer 6

sure

Answer 7

Adrian is using an indirect method to prove that segment DE is not parallel to segment BC in the triangle ABC shown:
He starts with the assumption that segment DE is parallel to segment BC.

Which inequality will he use to contradict the assumption?

Answer 8

5:3 ≠ 6:10

5:8 ≠ 6:4

5:8 ≠ 6:10

5:3 ≠ 5:6
I think its the third one

Answer 9

i second that

Answer 10

great! few more questions left! :)

Answer 11

yup you are right

Answer 12

The figure below shows a trapezoid, ABCD, having side AB parallel to side DC. The diagonals AC and BD intersect at point O.
If the length of AO is three times the length of CO, the length of BO is
one-third the length of AC

one-third the length of AB

three times the length of DO

three times the length of DC
I think its the third one

Answer 13

sorry iam not sure my self

Answer 14

The figure shows three right triangles. Triangles ABD, CAD, and CBA are similar.

Theorem: If two triangles are similar, the corresponding sides are in proportion.

Using the given theorem, which two statements help to prove that if segment BC is x, then x2 = 74?

Segment BC x segment DC = 49
Segment BC x segment BD = 35

Segment BC x segment DC = 49
Segment BC x segment BD = 25

Segment BC x segment DC = 25
Segment BC x segment BD = 35

Segment BC x segment DC = 25
Segment BC x segment BD = 49
I have no clue on this one

Answer 15

for the trapezoid one, you are correct

Answer 16

b i asume

Answer 17

The figure below shows segments KL and MN which intersect at point P. Segment KM is parallel to segment LN.
Which of these facts is used to prove that triangle KMP is similar to triangle LNP?

Angle KMP is congruent to angle LNP because they are vertical angles.

Angle KMP is congruent to angle LNP because they are alternate interior angles.

Angle KPM is congruent to angle LPN because alternate exterior angles are congruent.

Angle KPM is congruent to angle LPN because corresponding angles are congruent.

I think this one is B

Answer 18

am i right ninja tiger

Answer 19

hold on

Answer 20

sorry got to go

Answer 21

im eating and doing this at the same time

Answer 22

haha mghprenc......

Answer 23

@i_need_help_plz yeah i think you were right

Answer 24

yah the one before this is b and this is c or b butt i think b

Answer 25

@monet0223 you are right its b

Answer 26

haha butt

Answer 27

shes gone

Answer 28

haha @i_need_help_plz

Answer 29

i fanned u so if i need your help or u need mine just tag me

Answer 30

ok :) @i_need_help_plz

Answer 31

hellooooo!!!!!!!!!

Answer 32

no im not gone. sorry, I was working on some problems. Thanks! Thats all I needed! Thanks again so much!

Answer 33

welcome :)

Answer 34

home

Answer 35

yahhhhhh

Answer 36

?? @i_need_help_plz

Answer 37

what

Answer 38

welcome home

Answer 39

oooooooh i get it know :p @i_need_help_plz

Answer 40

now

Answer 41

nnnnnnnnooooooow

Answer 42

NOW!!!!!!!!!!!!!!!!!!!!!!!!

Answer 43

hello

Answer 44

yeah i do that a lot @i_need_help_plz

Answer 45

pshhhhhhh...... its ok