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help? pic in comments
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\[\frac{\sin(60)}{9.2}=\frac{\sin(B)}{10}\]\[\sin(B)=\frac{10\sin(60)}{9.2}\] \[B=\arcsin\left(\frac{10\sin(60)}{9.2}\right)\]
once you get that angle i can show you how to find the other one by looking at the picture
-.33?
seems unlikely
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me and calculators dont work well...
i haven't used one since y2k
calculators and i ...
in any case you get about \(70.28\)
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so B= 109.73?
lol, a negative angle seeming unlikely
and the other is \(180-70.28\)
anyway, nice explanation @satellite73 I couldn't have explained it better myself
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