I just need feedback to see if I am getting the material, anyone up for checking two questions??
@jim_thompson5910
both are incorrect
are they suppose to be switched?? What did I do wrong??
In the first one, AC is perpendicular to BD AC also cuts BD into two equal parts
so would it be perpendicular bisector, but i thought that angle bisector starts at a vertex and cuts the triangle to make both sides congruent.
we don't know if angle DAB is cut in half or not so we can't say AC is an angle bisector
Oh that make sense, so does that apply to the perpendicular bisector as well?
What do you mean?
Im so confused :(
Where are you stuck?
Im confused on the fact that its not an angle bisector. And how it could be any of the other answer choices.
Say we have this angle |dw:1405568040844:dw|
Now if we cut it in half |dw:1405568054749:dw| we create the angle bisector
we don't know if we've cut the angle in half in that first problem so we can't say for sure it's an angle bisector
Oh, I get it so, Would it be a perpendicular bisector because we know that BC is congruent to DC, because doesn't a perpendicular bisector create congruent sides?
yep, it cuts BD in half to create two congruent pieces
AC is also perpendicular to BD
So the answer would be perpendicular bisector because it creates two congruent pieces,
So whenever a problem states that two sides are perpendicular and names other congruent sides then would it automatically be perpendicular bisector
It might help to view it like this here is segment BD |dw:1405568710081:dw|
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