What is the length of the circle's radius?
|dw:1405567633689:dw| Does that help?
Yes very much thanks.
Do I take the sq. root of 25 then divide by 2?
Nope, no need to divide by 2 since the "hypotenuse" is the radius at every single x and y that satisfy this equation x^2+y^2=25. If you wanted the diameter, then you'd take the square root and multiply by 2.
So 10, then divide by 2 which is 5?
Wait nvm. 2.5?
No 10? Ugh...
The radius is 10!
Wot. I think you're overcomplicating this. Start over haha. No, the diameter is 10. The radius is 5.
Okay. Thank you. This is confusing.
So I take the square root of "c" then multiply that by 2, the divide by 2?
The equation of the circle is just saying that you have a triangle at a constant hypotenuse. Try to understand why the pythagorean theorem is the equation of a circle by drawing a bunch of different triangles in a circle: |dw:1405568037380:dw| See how all these triangles have a hypotenuse that are exactly the same, the radius? That's why x and y are variables.
It might take a little why to understand this, but once you get it, you'll not have to think very hard about it anymore and have a deeper understanding of how circles and triangles are related! =D
Thank you so so much. :)
Cool glad I could help.
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