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Geometry 8 Online
OpenStudy (anonymous):

Which ones are in the second quadrant?

OpenStudy (anonymous):

OpenStudy (zzr0ck3r):

so a point (a,b) is in the 2nd quadrant if a is negative and b is positive

OpenStudy (zzr0ck3r):

you with me?

OpenStudy (anonymous):

Right.

OpenStudy (zzr0ck3r):

the equation of a circle is \(r^2=(x-\color{blue}{a})^2+(y-\color{blue}{b})^2\)

OpenStudy (zzr0ck3r):

still with me?

OpenStudy (zzr0ck3r):

the minus signs are important here...

OpenStudy (anonymous):

That's the same thing as \[y ^{2}+x ^{2}=2(r)^{2}\]?

OpenStudy (zzr0ck3r):

no

OpenStudy (anonymous):

Isn't it when it's in a ( ) that means it's the opposite of what I see?

OpenStudy (anonymous):

Oh.

OpenStudy (zzr0ck3r):

I dont know where you keep getting that from

OpenStudy (anonymous):

I think I'm confusing formulas.

OpenStudy (anonymous):

I'll use the equation for a circle for this problem, then.

OpenStudy (zzr0ck3r):

use the equation I gave and look at your answers example the first one \((x+2)^2+(y-5)^2=9\) we should rewrite it so that we have a minus sign \((x-(-2))^2+(y-5)^2=9\) so \(a = -2\) and \(b = 5\) and like I said if a is negative and b is positive the center is in the 2nd quadrant

OpenStudy (anonymous):

Okay. I got that.

OpenStudy (zzr0ck3r):

the important part is that you realize why I rewrote it with the negative sign, and that is because that is the form we need to get it into before we can see what the value of a and b are.

OpenStudy (zzr0ck3r):

so what is the sign of a and b in the second one?

OpenStudy (anonymous):

x is positive and y is negative?

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