Question

PLEASE HELP
solve x^2-5x=3 with the quadratic formula!!

Answer 1

rewrite it in the form \(ax^2+bx+c=0\) then use the quadratic formula
\(x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\)

Answer 2

I know how... its just I need it and howe to solve it right away!

Answer 3

look up \(\huge \uparrow\)

Answer 4

there is that method and one other method, but if you don't like this one, I very much doubt you will like the other.

Answer 5

"I know how.."

I am confused.

Answer 6

no wait let me explain. I know how to do it. Its that Im in a hurry and was wondering if you could solve it because I have 5 others to solve!

Answer 7

you could have been done by now.

Answer 8

I have done it twice

Answer 9

alright...

Answer 10

We are not here to take test or do your homework for you, we are here to guide you to an answer.

Answer 11

its not homework! or a test

Answer 12

Well then why do you need it done? If its not homework or a test, then there is no point in me doing something I know how to do for practice.

Answer 13

Im doing it for my mom

Answer 14

Well we are not here to do her homework or take her test either:)

Answer 15

shhhh.. thats not what i meant

Answer 16

hmm I am still confused.

Answer 17

fine.. then could you help me figure it out?

Answer 18

yes

Answer 19

subtract 3 from both sides and you have \(x^2-5x-3=0\) do you see that?

Answer 20

\(ax^2+bx+c=0\)
\(x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\)

Answer 21

can you tell me what a=?

Answer 22

where did you get the 3 from?

Answer 23

\( x^2-5x=3\)

Answer 24

subtract 3 from both sides
\( x^2-5x-3=3-3\)
\(x^2-5x-3=0\)

Answer 25

oh wait!!

Answer 26

the reason we do this is to get it in the form \(ax^2+bx+c=0\) then we can use
\(x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\)

Answer 27

\[x^{2}-5x=3\]
There are 2 real solutions

The Work
\[x=\frac{ -b \pm \sqrt{b ^{2}- 4(a)(c)} }{ 2(a) }\]

\[x=\frac{ -5 \pm \sqrt{5 ^{2}- 4(1)(3)} }{ 2(1) }\]

\[\frac{ -5\pm \sqrt{13} }{ 2 }\]


Solutions:
x=−0.6972243622680054
x=−4.302775637731995

Answer 28

why would you do that @TwinYang ? when you see someone trying to do it them selves

Answer 29

If I was helping someone in a tutor lab would you just walk up and hand them the answer?

Answer 30

lame

Answer 31

not this problem...its x^2+4x-6=0

Answer 32

see now hes tryong to cheat you out of another one.

Answer 33

i already knew the answer

Answer 34

IM ASKING YOU ZZR0CK3R

Answer 35

fine