I am not able to find maxima of this function
\[\huge f(x)=x ^{5}-5x ^{4}+5x ^{3}-10\]
I got the first derivative as:- \[x ^{2}-4x+3\] So by setting them equal to zero i get x=1 or x=3 Now if i do the 2nd derivative test i get x = 2 which is MINIMA :(
The first derivative goes like this: 5x^4 - 20x^3 .....
yeah factor it out and set it equal to zero
f'(x) = 5x^4 - 20x^3 + 15x^2 = 0 5x^2(x^2 - 4x + 3) = 0 5x^2(x-3)(x-1) = 0 Critical Points are: x = 0, 1 and 3.
won't you move 5x^2 to the right?
No. You equate the first derivative to zero and solve for x.
What are all the values of x that will make the first derivative equal zero? x = 0, 1 and 3.
So, ok after this what we should do
Take the second derivative and test each critical point.
so 1 is a maxima point thanks
Correct.
Join our real-time social learning platform and learn together with your friends!