Question

7 square root of 3 end root minus 4 square root of 6 end root plus square root of 48 end root minus square root of 54

Answer 1

would it be:
11 square root of 6 end root minus 7 square root of 12
11 square root of 3 end root minus 7 square root of 6
negative 3 square root of 9
4 square root of 9

Answer 2

\[7\sqrt{3}-4\sqrt{6}+\sqrt{48}-\sqrt{54}\] Is the first part right?

Answer 3

The goal is to get all the radicands to be either a sqrt 3 or a sqrt 6 so you can combine the like radicands. simplify the sqt 48 and the sqrt 54.

Answer 4

@Cosmichaotic yes that is right

Answer 5

@IMStuck ok

Answer 6

@IMStuck i would use 6x8 and 6x9