7 square root of 3 end root minus 4 square root of 6 end root plus square root of 48 end root minus square root of 54

Question

anonymous · Answer

would it be: 
11 square root of 6 end root minus 7 square root of 12
	11 square root of 3 end root minus 7 square root of 6
	negative 3 square root of 9
	4 square root of 9

anonymous · Answer

$$7\sqrt{3}-4\sqrt{6}+\sqrt{48}-\sqrt{54}$$ Is the first part right?

imstuck · Answer

The goal is to get all the radicands to be either a sqrt 3 or a sqrt 6 so you can combine the like radicands.  simplify the sqt 48 and the sqrt 54.

anonymous · Answer

@Cosmichaotic yes that is right

anonymous · Answer

@IMStuck ok

anonymous · Answer

@IMStuck  i would use 6x8 and 6x9