Question

Can anyone verify if my answer is correct?

Answer 1

sure

Answer 2

\[y=\frac{ -3x^3+3x }{ \sqrt{2-x^2} }\]

Answer 3

I find it's derivative and got

Answer 4

\[y'=\frac{ 6x^4-24x^2+6 }{ (2-x^2)\sqrt{2-x^2} }\]

Answer 5

This is after I simplified as much as I could chop chop the juice.

Answer 6

but the raw derivative would be \[y'=\frac{ -9x^2\sqrt{2-x^2}+3\sqrt{2-x^2}-\frac{ 3x^4+3x^2 }{ \sqrt{2-x^2} } }{ 2-x^2 }\]

Answer 7

-3x^3+3x= ?

Answer 8

what do you mean?

Answer 9

it means -9x^2+3

Answer 10

You use quotient rule. Not power rule.

Answer 11

so

Answer 12

wait a min